Question
Answer
$$\dfrac{4a^2-36}{24-8a}=\dfrac{a+3}{-2}$$
Explanation
| $$ \begin{aligned}\frac{4a^2-36}{24-8a}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{a+3}{-2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4a^2-36}{24-8a} $ to $ \dfrac{a+3}{-2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4a-12}$. $$ \begin{aligned} \frac{4a^2-36}{24-8a} & =\frac{ \left( a+3 \right) \cdot \color{blue}{ \left( 4a-12 \right) }}{ \left( -2 \right) \cdot \color{blue}{ \left( 4a-12 \right) }} = \\[1ex] &= \frac{a+3}{-2} \end{aligned} $$ |
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Simplify Rational Expressions