Question
Answer
$$\dfrac{45-5a}{3a^2-28a+9}=-\dfrac{5}{3a-1}$$
Explanation
| $$ \begin{aligned}\frac{45-5a}{3a^2-28a+9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{5}{3a-1}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{45-5a}{3a^2-28a+9} $ to $ \dfrac{-5}{3a-1} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a-9}$. $$ \begin{aligned} \frac{45-5a}{3a^2-28a+9} & =\frac{ \left( -5 \right) \cdot \color{blue}{ \left( a-9 \right) }}{ \left( 3a-1 \right) \cdot \color{blue}{ \left( a-9 \right) }} = \\[1ex] &= \frac{-5}{3a-1} \end{aligned} $$ |
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Simplify Rational Expressions