Question
Answer
$$\dfrac{40x^2-30x+5}{4x-1}=10x-5$$
Explanation
| $$ \begin{aligned}\frac{40x^2-30x+5}{4x-1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x-5\end{aligned} $$ | |
| ① | Simplify $ \dfrac{40x^2-30x+5}{4x-1} $ to $ 10x-5$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4x-1}$. $$ \begin{aligned} \frac{40x^2-30x+5}{4x-1} & =\frac{ \left( 10x-5 \right) \cdot \color{blue}{ \left( 4x-1 \right) }}{ 1 \cdot \color{blue}{ \left( 4x-1 \right) }} = \\[1ex] &= \frac{10x-5}{1} =10x-5 \end{aligned} $$ |
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Simplify Rational Expressions