Question
Answer
$$\dfrac{4(2x-10x)}{8}=-\dfrac{32x}{8}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{4(2x-10x)}{8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8x-40x}{8} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-\frac{32x}{8}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( 2x-10x\right) $ $$ \color{blue}{4} \cdot \left( 2x-10x\right) = 8x-40x $$ |
| ② | Simplify numerator $$ \color{blue}{8x} \color{blue}{-40x} = \color{blue}{-32x} $$ |
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Simplify Rational Expressions