Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3x-5}{4x^2+12x+9}+\frac{4}{2x+3}-2\frac{x}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{11x+7}{4x^2+12x+9}-\frac{2x}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-8x^3-24x^2+15x+21}{12x^2+36x+27}\end{aligned} $$ | |
| ① | Add $ \dfrac{3x-5}{4x^2+12x+9} $ and $ \dfrac{4}{2x+3} $ to get $ \dfrac{ \color{purple}{ 11x+7 } }{ 4x^2+12x+9 }$. To add raitonal expressions, both fractions must have the same denominator. |
| ② | Multiply $2$ by $ \dfrac{x}{3} $ to get $ \dfrac{ 2x }{ 3 } $. Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2 \cdot \frac{x}{3} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} \cdot \frac{x}{3} \xlongequal{\text{Step 2}} \frac{ 2 \cdot x }{ 1 \cdot 3 } \xlongequal{\text{Step 3}} \frac{ 2x }{ 3 } \end{aligned} $$ |
| ③ | Subtract $ \dfrac{2x}{3} $ from $ \dfrac{11x+7}{4x^2+12x+9} $ to get $ \dfrac{ \color{purple}{ -8x^3-24x^2+15x+21 } }{ 12x^2+36x+27 }$. To subtract raitonal expressions, both fractions must have the same denominator. |