| $$ \begin{aligned}(3x-2)\cdot6x^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}18x^3-12x^2\end{aligned} $$ | |
| ① | $$ \left( \color{blue}{3x-2}\right) \cdot 6x^2 = 18x^3-12x^2 $$ |