Question
Answer
$$(3x^2+2x-1)(2x-3)=6x^3-5x^2-8x+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x^2+2x-1)(2x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^3-9x^2+4x^2-6x-2x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^3-5x^2-8x+3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x^2+2x-1}\right) $ by each term in $ \left( 2x-3\right) $. $$ \left( \color{blue}{3x^2+2x-1}\right) \cdot \left( 2x-3\right) = 6x^3-9x^2+4x^2-6x-2x+3 $$ |
| ② | Combine like terms: $$ 6x^3 \color{blue}{-9x^2} + \color{blue}{4x^2} \color{red}{-6x} \color{red}{-2x} +3 = 6x^3 \color{blue}{-5x^2} \color{red}{-8x} +3 $$ |
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