Question
Answer
$$\dfrac{3x^2-3}{x^2-1}=3$$
Explanation
| $$ \begin{aligned}\frac{3x^2-3}{x^2-1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3x^2-3}{x^2-1} $ to $ 3$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x^2-1}$. $$ \begin{aligned} \frac{3x^2-3}{x^2-1} & =\frac{ 3 \cdot \color{blue}{ \left( x^2-1 \right) }}{ 1 \cdot \color{blue}{ \left( x^2-1 \right) }} = \\[1ex] &= \frac{3}{1} =3 \end{aligned} $$ |
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Simplify Rational Expressions