Question
Answer
$$\dfrac{3x^2-27}{3x-9}=x+3$$
Explanation
| $$ \begin{aligned}\frac{3x^2-27}{3x-9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x+3\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3x^2-27}{3x-9} $ to $ x+3$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3x-9}$. $$ \begin{aligned} \frac{3x^2-27}{3x-9} & =\frac{ \left( x+3 \right) \cdot \color{blue}{ \left( 3x-9 \right) }}{ 1 \cdot \color{blue}{ \left( 3x-9 \right) }} = \\[1ex] &= \frac{x+3}{1} =x+3 \end{aligned} $$ |
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Simplify Rational Expressions