Question
Answer
$$\dfrac{3x^2-18+24}{2x-8}=\dfrac{3x^2+6}{2x-8}$$
Explanation
| $$ \begin{aligned}\frac{3x^2-18+24}{2x-8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x^2+6}{2x-8}\end{aligned} $$ | |
| ① | Simplify numerator $$ 3x^2 \color{blue}{-18} + \color{blue}{24} = 3x^2+ \color{blue}{6} $$ |
This page was created using
Simplify Rational Expressions