Question
Answer
$$\dfrac{3x^2-12}{8x^2-18+4}=\dfrac{3x^2-12}{8x^2-14}$$
Explanation
| $$ \begin{aligned}\frac{3x^2-12}{8x^2-18+4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x^2-12}{8x^2-14}\end{aligned} $$ | |
| ① | Simplify denominator $$ 8x^2 \color{blue}{-18} + \color{blue}{4} = 8x^2 \color{blue}{-14} $$ |
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Simplify Rational Expressions