Question
Answer
$$\dfrac{3u^2-u}{18u-6}=\dfrac{u}{6}$$
Explanation
| $$ \begin{aligned}\frac{3u^2-u}{18u-6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{u}{6}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3u^2-u}{18u-6} $ to $ \dfrac{u}{6} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3u-1}$. $$ \begin{aligned} \frac{3u^2-u}{18u-6} & =\frac{ u \cdot \color{blue}{ \left( 3u-1 \right) }}{ 6 \cdot \color{blue}{ \left( 3u-1 \right) }} = \\[1ex] &= \frac{u}{6} \end{aligned} $$ |
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Simplify Rational Expressions