Question
Answer
$$\dfrac{3m^2-25m+42}{6-m}=\dfrac{3m-7}{-1}$$
Explanation
| $$ \begin{aligned}\frac{3m^2-25m+42}{6-m}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3m-7}{-1}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3m^2-25m+42}{6-m} $ to $ \dfrac{3m-7}{-1} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m-6}$. $$ \begin{aligned} \frac{3m^2-25m+42}{6-m} & =\frac{ \left( 3m-7 \right) \cdot \color{blue}{ \left( m-6 \right) }}{ \left( -1 \right) \cdot \color{blue}{ \left( m-6 \right) }} = \\[1ex] &= \frac{3m-7}{-1} \end{aligned} $$ |
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Simplify Rational Expressions