Question
Answer
$$\dfrac{\dfrac{3g-5}{15g^2+20g}}{6}=\dfrac{3g-5}{90g^2+120g}$$
Explanation
| $$ \begin{aligned}\frac{\frac{3g-5}{15g^2+20g}}{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3g-5}{90g^2+120g}\end{aligned} $$ | |
| ① | Divide $ \dfrac{3g-5}{15g^2+20g} $ by $ 6 $ to get $ \dfrac{ 3g-5 }{ 90g^2+120g } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{3g-5}{15g^2+20g} }{6} & \xlongequal{\text{Step 1}} \frac{3g-5}{15g^2+20g} \cdot \frac{\color{blue}{1}}{\color{blue}{6}} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \left( 3g-5 \right) \cdot 1 }{ \left( 15g^2+20g \right) \cdot 6 } \xlongequal{\text{Step 3}} \frac{ 3g-5 }{ 90g^2+120g } \end{aligned} $$ |
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Simplify Rational Expressions