Question
Answer
$$\dfrac{3a^2+6a-24}{a^2-7a+10}=\dfrac{3a+12}{a-5}$$
Explanation
| $$ \begin{aligned}\frac{3a^2+6a-24}{a^2-7a+10}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3a+12}{a-5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3a^2+6a-24}{a^2-7a+10} $ to $ \dfrac{3a+12}{a-5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a-2}$. $$ \begin{aligned} \frac{3a^2+6a-24}{a^2-7a+10} & =\frac{ \left( 3a+12 \right) \cdot \color{blue}{ \left( a-2 \right) }}{ \left( a-5 \right) \cdot \color{blue}{ \left( a-2 \right) }} = \\[1ex] &= \frac{3a+12}{a-5} \end{aligned} $$ |
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Simplify Rational Expressions