Question
Answer
$$\dfrac{30k-20}{90}k=\dfrac{30k^2-20k}{90}$$
Explanation
| $$ \begin{aligned}\frac{30k-20}{90}k& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{30k^2-20k}{90}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{30k-20}{90} $ by $ k $ to get $ \dfrac{ 30k^2-20k }{ 90 } $. Step 1: Write $ k $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{30k-20}{90} \cdot k & \xlongequal{\text{Step 1}} \frac{30k-20}{90} \cdot \frac{k}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 30k-20 \right) \cdot k }{ 90 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 30k^2-20k }{ 90 } \end{aligned} $$ |
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Simplify Rational Expressions