Question
Answer
$$\dfrac{\dfrac{3}{2x^2}}{\dfrac{10}{7x^2}}=\dfrac{21x^2}{20x^2}$$
Explanation
| $$ \begin{aligned}\frac{\frac{3}{2x^2}}{\frac{10}{7x^2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{21x^2}{20x^2}\end{aligned} $$ | |
| ① | Divide $ \dfrac{3}{2x^2} $ by $ \dfrac{10}{7x^2} $ to get $ \dfrac{ 21x^2 }{ 20x^2 } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{3}{2x^2} }{ \frac{\color{blue}{10}}{\color{blue}{7x^2}} } & \xlongequal{\text{Step 1}} \frac{3}{2x^2} \cdot \frac{\color{blue}{7x^2}}{\color{blue}{10}} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 3 \cdot 7x^2 }{ 2x^2 \cdot 10 } \xlongequal{\text{Step 3}} \frac{ 21x^2 }{ 20x^2 } \end{aligned} $$ |
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Simplify Rational Expressions