Question
Answer
$$2y+2-8(2y-1)=-14y+10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2y+2-8(2y-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2y+2-(16y-8) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2y+2-16y+8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-14y+10\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{8} $ by $ \left( 2y-1\right) $ $$ \color{blue}{8} \cdot \left( 2y-1\right) = 16y-8 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 16y-8 \right) = -16y+8 $$ |
| ③ | Combine like terms: $$ \color{blue}{2y} + \color{red}{2} \color{blue}{-16y} + \color{red}{8} = \color{blue}{-14y} + \color{red}{10} $$ |
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