Question
Answer
$$\dfrac{2y^2+9y-18}{4y^2-6y}=\dfrac{y+6}{2y}$$
Explanation
| $$ \begin{aligned}\frac{2y^2+9y-18}{4y^2-6y}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y+6}{2y}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2y^2+9y-18}{4y^2-6y} $ to $ \dfrac{y+6}{2y} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2y-3}$. $$ \begin{aligned} \frac{2y^2+9y-18}{4y^2-6y} & =\frac{ \left( y+6 \right) \cdot \color{blue}{ \left( 2y-3 \right) }}{ 2y \cdot \color{blue}{ \left( 2y-3 \right) }} = \\[1ex] &= \frac{y+6}{2y} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions