Question
Answer
$$\dfrac{2x^3+13x^2+15x}{x^2+5x}=2x+3$$
Explanation
| $$ \begin{aligned}\frac{2x^3+13x^2+15x}{x^2+5x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x+3\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2x^3+13x^2+15x}{x^2+5x} $ to $ 2x+3$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x^2+5x}$. $$ \begin{aligned} \frac{2x^3+13x^2+15x}{x^2+5x} & =\frac{ \left( 2x+3 \right) \cdot \color{blue}{ \left( x^2+5x \right) }}{ 1 \cdot \color{blue}{ \left( x^2+5x \right) }} = \\[1ex] &= \frac{2x+3}{1} =2x+3 \end{aligned} $$ |
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Simplify Rational Expressions