Question
Answer
$$\dfrac{2x^2+18x}{x^2+9x}=2$$
Explanation
| $$ \begin{aligned}\frac{2x^2+18x}{x^2+9x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2x^2+18x}{x^2+9x} $ to $ 2$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x^2+9x}$. $$ \begin{aligned} \frac{2x^2+18x}{x^2+9x} & =\frac{ 2 \cdot \color{blue}{ \left( x^2+9x \right) }}{ 1 \cdot \color{blue}{ \left( x^2+9x \right) }} = \\[1ex] &= \frac{2}{1} =2 \end{aligned} $$ |
This page was created using
Simplify Rational Expressions