Question
Answer
$$\dfrac{2x^2}{3x^3}\cdot\dfrac{3}{x-6}=\dfrac{6x^2}{3x^4-18x^3}$$
Explanation
| $$ \begin{aligned}\frac{2x^2}{3x^3}\cdot\frac{3}{x-6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6x^2}{3x^4-18x^3}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{2x^2}{3x^3} $ by $ \dfrac{3}{x-6} $ to get $ \dfrac{ 6x^2 }{ 3x^4-18x^3 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{2x^2}{3x^3} \cdot \frac{3}{x-6} & \xlongequal{\text{Step 1}} \frac{ 2x^2 \cdot 3 }{ 3x^3 \cdot \left( x-6 \right) } \xlongequal{\text{Step 2}} \frac{ 6x^2 }{ 3x^4-18x^3 } \end{aligned} $$ |
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