Question
Answer
$$\dfrac{2r^3-4r^2}{r^2-2r}=2r$$
Explanation
| $$ \begin{aligned}\frac{2r^3-4r^2}{r^2-2r}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2r\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2r^3-4r^2}{r^2-2r} $ to $ 2r$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{r^2-2r}$. $$ \begin{aligned} \frac{2r^3-4r^2}{r^2-2r} & =\frac{ 2r \cdot \color{blue}{ \left( r^2-2r \right) }}{ 1 \cdot \color{blue}{ \left( r^2-2r \right) }} = \\[1ex] &= \frac{2r}{1} =2r \end{aligned} $$ |
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Simplify Rational Expressions