Question
Answer
$$\dfrac{2p^3-20p^2+32p}{p-2}=2p^2-16p$$
Explanation
| $$ \begin{aligned}\frac{2p^3-20p^2+32p}{p-2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2p^2-16p\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2p^3-20p^2+32p}{p-2} $ to $ 2p^2-16p$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{p-2}$. $$ \begin{aligned} \frac{2p^3-20p^2+32p}{p-2} & =\frac{ \left( 2p^2-16p \right) \cdot \color{blue}{ \left( p-2 \right) }}{ 1 \cdot \color{blue}{ \left( p-2 \right) }} = \\[1ex] &= \frac{2p^2-16p}{1} =2p^2-16p \end{aligned} $$ |
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Simplify Rational Expressions