Question
Answer
$$\dfrac{2n^2+10n-100}{7n^3+62n^2-80n}=\dfrac{2n-10}{7n^2-8n}$$
Explanation
| $$ \begin{aligned}\frac{2n^2+10n-100}{7n^3+62n^2-80n}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2n-10}{7n^2-8n}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2n^2+10n-100}{7n^3+62n^2-80n} $ to $ \dfrac{2n-10}{7n^2-8n} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n+10}$. $$ \begin{aligned} \frac{2n^2+10n-100}{7n^3+62n^2-80n} & =\frac{ \left( 2n-10 \right) \cdot \color{blue}{ \left( n+10 \right) }}{ \left( 7n^2-8n \right) \cdot \color{blue}{ \left( n+10 \right) }} = \\[1ex] &= \frac{2n-10}{7n^2-8n} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions