Question
Answer
$$\dfrac{2b^2-6b}{5b^2-15b}=\dfrac{2}{5}$$
Explanation
| $$ \begin{aligned}\frac{2b^2-6b}{5b^2-15b}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2}{5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2b^2-6b}{5b^2-15b} $ to $ \dfrac{2}{5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{b^2-3b}$. $$ \begin{aligned} \frac{2b^2-6b}{5b^2-15b} & =\frac{ 2 \cdot \color{blue}{ \left( b^2-3b \right) }}{ 5 \cdot \color{blue}{ \left( b^2-3b \right) }} = \\[1ex] &= \frac{2}{5} \end{aligned} $$ |
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Simplify Rational Expressions