Question
Answer
$$\dfrac{2a^2+4a-6}{10a^2+40a+30}=\dfrac{a-1}{5a+5}$$
Explanation
| $$ \begin{aligned}\frac{2a^2+4a-6}{10a^2+40a+30}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{a-1}{5a+5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2a^2+4a-6}{10a^2+40a+30} $ to $ \dfrac{a-1}{5a+5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2a+6}$. $$ \begin{aligned} \frac{2a^2+4a-6}{10a^2+40a+30} & =\frac{ \left( a-1 \right) \cdot \color{blue}{ \left( 2a+6 \right) }}{ \left( 5a+5 \right) \cdot \color{blue}{ \left( 2a+6 \right) }} = \\[1ex] &= \frac{a-1}{5a+5} \end{aligned} $$ |
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Simplify Rational Expressions