| $$ \begin{aligned}\frac{2a^2+10a}{3a^2+15a}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2}{3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2a^2+10a}{3a^2+15a} $ to $ \dfrac{2}{3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a^2+5a}$. $$ \begin{aligned} \frac{2a^2+10a}{3a^2+15a} & =\frac{ 2 \cdot \color{blue}{ \left( a^2+5a \right) }}{ 3 \cdot \color{blue}{ \left( a^2+5a \right) }} = \\[1ex] &= \frac{2}{3} \end{aligned} $$ |