Question
Answer
$$\dfrac{25x-15}{25x^3-9x}=\dfrac{5}{5x^2+3x}$$
Explanation
| $$ \begin{aligned}\frac{25x-15}{25x^3-9x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5}{5x^2+3x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{25x-15}{25x^3-9x} $ to $ \dfrac{5}{5x^2+3x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x-3}$. $$ \begin{aligned} \frac{25x-15}{25x^3-9x} & =\frac{ 5 \cdot \color{blue}{ \left( 5x-3 \right) }}{ \left( 5x^2+3x \right) \cdot \color{blue}{ \left( 5x-3 \right) }} = \\[1ex] &= \frac{5}{5x^2+3x} \end{aligned} $$ |
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Simplify Rational Expressions