Question
Answer
$$\dfrac{25s^3-4s}{10s-4}=\dfrac{5s^2+2s}{2}$$
Explanation
| $$ \begin{aligned}\frac{25s^3-4s}{10s-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5s^2+2s}{2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{25s^3-4s}{10s-4} $ to $ \dfrac{5s^2+2s}{2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5s-2}$. $$ \begin{aligned} \frac{25s^3-4s}{10s-4} & =\frac{ \left( 5s^2+2s \right) \cdot \color{blue}{ \left( 5s-2 \right) }}{ 2 \cdot \color{blue}{ \left( 5s-2 \right) }} = \\[1ex] &= \frac{5s^2+2s}{2} \end{aligned} $$ |
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Simplify Rational Expressions