Question
Answer
$$\dfrac{24x^2-72x}{8}x=\dfrac{24x^3-72x^2}{8}$$
Explanation
| $$ \begin{aligned}\frac{24x^2-72x}{8}x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{24x^3-72x^2}{8}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{24x^2-72x}{8} $ by $ x $ to get $ \dfrac{ 24x^3-72x^2 }{ 8 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{24x^2-72x}{8} \cdot x & \xlongequal{\text{Step 1}} \frac{24x^2-72x}{8} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 24x^2-72x \right) \cdot x }{ 8 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 24x^3-72x^2 }{ 8 } \end{aligned} $$ |
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Simplify Rational Expressions