Question
Answer
$$\dfrac{24x^2-200x-144}{24x+16}=x-9$$
Explanation
| $$ \begin{aligned}\frac{24x^2-200x-144}{24x+16}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-9\end{aligned} $$ | |
| ① | Simplify $ \dfrac{24x^2-200x-144}{24x+16} $ to $ x-9$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{24x+16}$. $$ \begin{aligned} \frac{24x^2-200x-144}{24x+16} & =\frac{ \left( x-9 \right) \cdot \color{blue}{ \left( 24x+16 \right) }}{ 1 \cdot \color{blue}{ \left( 24x+16 \right) }} = \\[1ex] &= \frac{x-9}{1} =x-9 \end{aligned} $$ |
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Simplify Rational Expressions