Question
Answer
$$\dfrac{20x^2+30x}{4x^4+6x^3}=\dfrac{5}{x^2}$$
Explanation
| $$ \begin{aligned}\frac{20x^2+30x}{4x^4+6x^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5}{x^2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{20x^2+30x}{4x^4+6x^3} $ to $ \dfrac{5}{x^2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4x^2+6x}$. $$ \begin{aligned} \frac{20x^2+30x}{4x^4+6x^3} & =\frac{ 5 \cdot \color{blue}{ \left( 4x^2+6x \right) }}{ x^2 \cdot \color{blue}{ \left( 4x^2+6x \right) }} = \\[1ex] &= \frac{5}{x^2} \end{aligned} $$ |
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Simplify Rational Expressions