Question
Answer
$$\dfrac{16x^2+4x^2+2x}{-2x}=\dfrac{20x^2+2x}{-2x}$$
Explanation
| $$ \begin{aligned}\frac{16x^2+4x^2+2x}{-2x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{20x^2+2x}{-2x}\end{aligned} $$ | |
| ① | Simplify numerator $$ \color{blue}{16x^2} + \color{blue}{4x^2} +2x = \color{blue}{20x^2} +2x $$ |
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Simplify Rational Expressions