Question
Answer
$$\dfrac{16x^2-40x}{24}x^3=\dfrac{16x^5-40x^4}{24}$$
Explanation
| $$ \begin{aligned}\frac{16x^2-40x}{24}x^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{16x^5-40x^4}{24}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{16x^2-40x}{24} $ by $ x^3 $ to get $ \dfrac{ 16x^5-40x^4 }{ 24 } $. Step 1: Write $ x^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{16x^2-40x}{24} \cdot x^3 & \xlongequal{\text{Step 1}} \frac{16x^2-40x}{24} \cdot \frac{x^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 16x^2-40x \right) \cdot x^3 }{ 24 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 16x^5-40x^4 }{ 24 } \end{aligned} $$ |
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