Question
Answer
$$\dfrac{16m^2-25}{4m+5}=4m-5$$
Explanation
| $$ \begin{aligned}\frac{16m^2-25}{4m+5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4m-5\end{aligned} $$ | |
| ① | Simplify $ \dfrac{16m^2-25}{4m+5} $ to $ 4m-5$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4m+5}$. $$ \begin{aligned} \frac{16m^2-25}{4m+5} & =\frac{ \left( 4m-5 \right) \cdot \color{blue}{ \left( 4m+5 \right) }}{ 1 \cdot \color{blue}{ \left( 4m+5 \right) }} = \\[1ex] &= \frac{4m-5}{1} =4m-5 \end{aligned} $$ |
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Simplify Rational Expressions