Question
Answer
$$\dfrac{16a^2b^4}{3ab^3}\dfrac{6a^2b^3}{8a^5b}=\dfrac{96a^4b^7}{24a^6b^4}$$
Explanation
| $$ \begin{aligned}\frac{16a^2b^4}{3ab^3}\frac{6a^2b^3}{8a^5b}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{96a^4b^7}{24a^6b^4}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{16a^2b^4}{3ab^3} $ by $ \dfrac{6a^2b^3}{8a^5b} $ to get $ \dfrac{ 96a^4b^7 }{ 24a^6b^4 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{16a^2b^4}{3ab^3} \cdot \frac{6a^2b^3}{8a^5b} & \xlongequal{\text{Step 1}} \frac{ 16a^2b^4 \cdot 6a^2b^3 }{ 3ab^3 \cdot 8a^5b } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 96a^4b^7 }{ 24a^6b^4 } \end{aligned} $$ |
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Simplify Rational Expressions