Question
Answer
$$\dfrac{12x^2-30x}{20x^3-50x^2}=\dfrac{3}{5x}$$
Explanation
| $$ \begin{aligned}\frac{12x^2-30x}{20x^3-50x^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{5x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{12x^2-30x}{20x^3-50x^2} $ to $ \dfrac{3}{5x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4x^2-10x}$. $$ \begin{aligned} \frac{12x^2-30x}{20x^3-50x^2} & =\frac{ 3 \cdot \color{blue}{ \left( 4x^2-10x \right) }}{ 5x \cdot \color{blue}{ \left( 4x^2-10x \right) }} = \\[1ex] &= \frac{3}{5x} \end{aligned} $$ |
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Simplify Rational Expressions