Question
Answer
$$\dfrac{10x^2+50x+40}{5x+5}=2x+8$$
Explanation
| $$ \begin{aligned}\frac{10x^2+50x+40}{5x+5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x+8\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10x^2+50x+40}{5x+5} $ to $ 2x+8$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x+5}$. $$ \begin{aligned} \frac{10x^2+50x+40}{5x+5} & =\frac{ \left( 2x+8 \right) \cdot \color{blue}{ \left( 5x+5 \right) }}{ 1 \cdot \color{blue}{ \left( 5x+5 \right) }} = \\[1ex] &= \frac{2x+8}{1} =2x+8 \end{aligned} $$ |
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Simplify Rational Expressions