| $$ \begin{aligned}\frac{10x^2+14x}{5x+7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10x^2+14x}{5x+7} $ to $ 2x$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x+7}$. $$ \begin{aligned} \frac{10x^2+14x}{5x+7} & =\frac{ 2x \cdot \color{blue}{ \left( 5x+7 \right) }}{ 1 \cdot \color{blue}{ \left( 5x+7 \right) }} = \\[1ex] &= \frac{2x}{1} =2x \end{aligned} $$ |