| $$ \begin{aligned}\frac{10x^2-30x}{x-3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10x^2-30x}{x-3} $ to $ 10x$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-3}$. $$ \begin{aligned} \frac{10x^2-30x}{x-3} & =\frac{ 10x \cdot \color{blue}{ \left( x-3 \right) }}{ 1 \cdot \color{blue}{ \left( x-3 \right) }} = \\[1ex] &= \frac{10x}{1} =10x \end{aligned} $$ |