Question
Answer
$$\dfrac{10q^2+7q}{10q+7}=q$$
Explanation
| $$ \begin{aligned}\frac{10q^2+7q}{10q+7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}q\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10q^2+7q}{10q+7} $ to $ q$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{10q+7}$. $$ \begin{aligned} \frac{10q^2+7q}{10q+7} & =\frac{ q \cdot \color{blue}{ \left( 10q+7 \right) }}{ 1 \cdot \color{blue}{ \left( 10q+7 \right) }} = \\[1ex] &= \frac{q}{1} =q \end{aligned} $$ |
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Simplify Rational Expressions