Question
Answer
$$\dfrac{10m^3+20m^2}{15m^3+15m^2-30m}=\dfrac{2m}{3m-3}$$
Explanation
| $$ \begin{aligned}\frac{10m^3+20m^2}{15m^3+15m^2-30m}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2m}{3m-3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10m^3+20m^2}{15m^3+15m^2-30m} $ to $ \dfrac{2m}{3m-3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5m^2+10m}$. $$ \begin{aligned} \frac{10m^3+20m^2}{15m^3+15m^2-30m} & =\frac{ 2m \cdot \color{blue}{ \left( 5m^2+10m \right) }}{ \left( 3m-3 \right) \cdot \color{blue}{ \left( 5m^2+10m \right) }} = \\[1ex] &= \frac{2m}{3m-3} \end{aligned} $$ |
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