Question
Answer
$$\dfrac{10j^2-3j}{10j-3}=j$$
Explanation
| $$ \begin{aligned}\frac{10j^2-3j}{10j-3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}j\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10j^2-3j}{10j-3} $ to $ j$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{10j-3}$. $$ \begin{aligned} \frac{10j^2-3j}{10j-3} & =\frac{ j \cdot \color{blue}{ \left( 10j-3 \right) }}{ 1 \cdot \color{blue}{ \left( 10j-3 \right) }} = \\[1ex] &= \frac{j}{1} =j \end{aligned} $$ |
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Simplify Rational Expressions