Question
Answer
$$\dfrac{1-9x^2}{12x-4}=\dfrac{-3x-1}{4}$$
Explanation
| $$ \begin{aligned}\frac{1-9x^2}{12x-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-3x-1}{4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{1-9x^2}{12x-4} $ to $ \dfrac{-3x-1}{4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{3x-1}$. $$ \begin{aligned} \frac{1-9x^2}{12x-4} & =\frac{ \left( -3x-1 \right) \cdot \color{blue}{ \left( 3x-1 \right) }}{ 4 \cdot \color{blue}{ \left( 3x-1 \right) }} = \\[1ex] &= \frac{-3x-1}{4} \end{aligned} $$ |
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Simplify Rational Expressions