Question
Answer
$$\dfrac{1-2x}{4x^2-2x}=-\dfrac{1}{2x}$$
Explanation
| $$ \begin{aligned}\frac{1-2x}{4x^2-2x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{1}{2x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{1-2x}{4x^2-2x} $ to $ \dfrac{-1}{2x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2x-1}$. $$ \begin{aligned} \frac{1-2x}{4x^2-2x} & =\frac{ \left( -1 \right) \cdot \color{blue}{ \left( 2x-1 \right) }}{ 2x \cdot \color{blue}{ \left( 2x-1 \right) }} = \\[1ex] &= \frac{-1}{2x} \end{aligned} $$ |
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Simplify Rational Expressions