Question
Answer
$$\dfrac{-5x+7}{7}+\dfrac{-6x+5}{7}=\dfrac{-11x+12}{7}$$
Explanation
| $$ \begin{aligned}\frac{-5x+7}{7}+\frac{-6x+5}{7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-11x+12}{7}\end{aligned} $$ | |
| ① | Add $ \dfrac{-5x+7}{7} $ and $ \dfrac{-6x+5}{7} $ to get $ \dfrac{-11x+12}{7} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{-5x+7}{7} + \frac{-6x+5}{7} & = \frac{-5x+7}{\color{blue}{7}} + \frac{-6x+5}{\color{blue}{7}} =\frac{ -5x+7 + \left( -6x+5 \right) }{ \color{blue}{ 7 }} = \\[1ex] &= \frac{-11x+12}{7} \end{aligned} $$ |
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