Question
Answer
$$(-2y^4z^3)^3(3x^2y^2z)^2=-72x^4y^{16}z^{11}$$
Explanation
| $$ \begin{aligned}(-2y^4z^3)^3(3x^2y^2z)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8y^{12}z^99x^4y^4z^2 \xlongequal{ } \\[1 em] & \xlongequal{ }-72x^4y^{16}z^{11}\end{aligned} $$ | |
| ① | $$ \left( -2y^4z^3 \right)^3 = (-2)^3 \left( y^4 \right)^3 \left( z^3 \right)^3 = -8y^{12}z^9 $$$$ \left( 3x^2y^2z \right)^2 = 3^2 \left( x^2 \right)^2 \left( y^2 \right)^2z^2 = 9x^4y^4z^2 $$ |
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