Question
Answer
$$(-2x-5)(x^2+1)=-2x^3-5x^2-2x-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-2x-5)(x^2+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-2x^3-2x-5x^2-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2x^3-5x^2-2x-5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-2x-5}\right) $ by each term in $ \left( x^2+1\right) $. $$ \left( \color{blue}{-2x-5}\right) \cdot \left( x^2+1\right) = -2x^3-2x-5x^2-5 $$ |
| ② | Combine like terms: $$ -2x^3-5x^2-2x-5 = -2x^3-5x^2-2x-5 $$ |
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