Question
Answer
$$\dfrac{\dfrac{9x^3}{7}}{\dfrac{6}{5x^3}}=\dfrac{45x^6}{42}$$
Explanation
| $$ \begin{aligned}\frac{\frac{9x^3}{7}}{\frac{6}{5x^3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{45x^6}{42}\end{aligned} $$ | |
| ① | Divide $ \dfrac{9x^3}{7} $ by $ \dfrac{6}{5x^3} $ to get $ \dfrac{ 45x^6 }{ 42 } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{9x^3}{7} }{ \frac{\color{blue}{6}}{\color{blue}{5x^3}} } & \xlongequal{\text{Step 1}} \frac{9x^3}{7} \cdot \frac{\color{blue}{5x^3}}{\color{blue}{6}} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 9x^3 \cdot 5x^3 }{ 7 \cdot 6 } \xlongequal{\text{Step 3}} \frac{ 45x^6 }{ 42 } \end{aligned} $$ |
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Simplify Rational Expressions